If you rotate the hinge to angle X above the horizon, light coming in from an altitude angle of 2X (=zenith angle of 90deg-2X) will get reflected to into horizontal rays inside the tube.

So you don’t need a mount with adjustable altitude angle - the hinge accomplishes that.

There are a few typst packages for making presentation slides. Which one did you use?

No love for GNU IceCat?

Did you choose components and plan the connections on the perfboard yourself?

Also what was the original like? Would things work if you replace for example the transformer input side either the new kit and keep the output side the same?

Were you modding an existing power supply or making one from scratch?

Anything that’s updated with the OS can be rolled back. Now Windows is Windows so Crowdstrike handles things it’s own way. But I bet if Canonical or RedHat were to make their own versions of Crowdstrike, they would push updates through the o regular packages repo, allowing it to be rolled back.

Thanks! I will!

Please share both!

Awesome! Do you plan on publicly sharing the source code? I’d like to make a white on black background version.

I don’t understand your question, but are you talking about the sigmoid or arctan function?

Since this is a Rust comm, will you at least post an example using your tool with Rust?

They will upstream stuff, but sadly they are not going to mainline.

https://mastodon.social/@GranPC/112690143171368646

No. It uses Hallium (Android kernel, basically).

It’s already delivered - a Mastodon user got one.

But getting an OEM to make a phone under your brand is easy. The real question is how long will they keep the software maintained?

These people seem like passionate Linux enthusiasts, so one can hope.

According to the Librem people: this is Android kernel (& other low level stuff) with Debian userspace, not a true Debian phone. https://social.librem.one/@dos/112686932765355105

If I give you the entire real line except the point at zero, what will you pick? Whatever you decide on, there will always be a number closer to zero then that.

They have to get smaller to fit the problem statement- if all levers are the same size or have some nonzero minimum size then the full set of levers would be countable!

Now we play the game again 🤓. I start by removing the levers in the field/scale of view of your microscope’s default orientation.

But look at the picture: the levers are not all the same size- they get progressively smaller until (I assume from the ellipsis) they become infinitesimally small. If a cluster has this dense side facing you, then you won’t “see” a lever at all. You would only see a uniform sea of gray or whatever color the levers are. You now have to choose where to zoom in to see your first lever.

This reply applies to @Cube6392@beehaw.org’s comment too.

It might sound trivial but it is not! Imagine there is a lever at every point on the real number line; easy enough right? you might pick the lever at 0 as your “first” lever. Now imagine in another cluster I remove all the integer levers. You might say, pick the lever at 0.5. Now I remove all rational levers. You say, pick sqrt(2). Now I remove all algebraic numbers. On and on…

If we keep playing this game, can you keep coming up with which lever to pick indefinitely (as long as I haven’t removed all the levers)? If you think you can, that means you believe in the Axiom of Countable Choice.

Believing the axiom of countable choice is still not sufficient for this meme. Because now there are uncountably many clusters, meaning we can’t simply play the pick-a-lever game step-by-step; you have to pick levers continuously at every instant in time.