Imnecomrade [none/use name]

Imnecomrade - pronounced “I am any comrade”

Techie, hippie, commie nerd

  • 42 Posts
  • 103 Comments
Joined 6 months ago
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Cake day: May 16th, 2024

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  • Perhaps, I like to give the benefit of the doubt. There is the line “We don’t put folks to death for having different opinions,” which seems to have at least a hint of sarcasm given the mass shootings that occur in America frequently.

    Sometimes his songs are a bit “both sides” or liberal/(non-ML) anarchist, but I enjoy listening to them by giving them a socialist interpretation, though some lines it’s hard to do and I just ignore them. I also hope he grows and develops his consciousness more (as well as his fans), and sometimes it’s nice seeing an artist do so and witnessing their journey as they express it within their art.











  • 2x still means 2 * x.

    https://www.wolframalpha.com/input?i=6%2F2x

    x is still multiplied last. There’s not a rule for implied multiplication shorthand preceding operations to the left. You still need to wrap 2x in parentheses if you want the operation to occur first.

    https://www.wolframalpha.com/input?i=6%2F(2x)

    This isn’t like a polynomial like ax^2 + bx + c as division is done between 6 and 2 before multiplication with x. Typically you wouldn’t see such an equation (which is intended to trick you) as normally addition or subtraction would occur like in a polynomial or another variable equation (such as a linear graph), which would be done after the exponents, multiplication, and division with the variables are calculated. In the instance you wrote, it should be written as (6/2)x, or 3x, to avoid obscuring the equation. Though you intended for 6/(2x), or 3/x.

    And no worries, comrade, I’m just meaning to help since I am good at math and like helping people (I don’t mean this in an egotistical way). I’m not taking offense, and I am not meaning to offend anyone.


  • 2(1 + 2) does imply multiplication: 2 * (1 + 2). The reason it counts as one term, as I noted below, is because it is inside a two-dimensional fraction which has implicit parathenses in the numerator, denominator, and the fraction itself. The first equation is actually ((6) / (2(1 + 2))). When a fraction is written in two dimensions instead of a single string, the division between the numerator and the denominator is supposed to be done last.

    The first equation is not 6 / 2(1 + 2). If it was, this means you get (6 / 2) * (1 + 2) as in the second equation, which means (1 + 2) is moved up to the numerator ((6(1+2)) / 2 = (6 / 2) * (1 + 2)), which means the two problems are not equal to each other. I believe this is the point of the “joke”.



  • Assuming the first way is written correctly, the equation is actually 6 / (2 * (1 + 2)). The (1 + 2) is still inside the denominator. So it is solved as follows:

    6 / (2 * (1 + 2))

    6 / (2 * 3)

    6 / 6

    1

    The second equation incorrectly takes out the (1 + 2) and places it as the numerator on the side. In order to take that piece out correctly, it would have to be: (6 / 2) * (1 / (1 + 2))

    And to solve it, it would look like as follows:

    (6 / 2) * (1 / (1 + 2))

    3 * (1 / (1 + 2))

    3 * (1 / 3)

    3 / 3

    1

    Also, 3 * 3 = 9 in regards to second incorrect equation (incorrect meaning the second incorrectly refactored equation from the pic that you answered correctly up until the last operation).

    I think The_sleepy_woke_dialectic forgot to put parentheses around the denominator, but I believe it was meant to be interpreted as the entire denominator as shown in the pic.