Is d/dx x^2 really equal to d/dx (x+x+x+…+x)? Inserting some value for x seems to break that part. Say x=5:

d/dx 5^2=10 and

d/dx (x+x+x+x+x)=d/dx 5x=5

10 ≠ 5

I understand that x^2, (x+x+x+…+x), and x*x are the same. But its equivalent to doing d/dx x*x =x as d/dx n*x=n. Again this results in 2x=x or 2=1.

The mistake is to treat a variable as a constant and deriving in that way. Doing a sum x times means you have an unaccounted variable when you do d/dx (x+x+x+…+x), this is not 1+1+1+…+1 x times. i.e. The rate of change of one of the x is not incorporated into the derivative.

Mexico had a land reform in the first half of the XX century in which land was distributed to agricultural workers, that makes many of the poor have a family member that owns a house or a small plot of land.

Extended family relations also usually result in having someone willing to take you in no matter what condition you’re in. There’s still homeless people but nothing like the US and parts of Europe