• TranquilTurbulence@lemmy.zip
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      1 day ago

      E=mc^2 should cover it, proper physicists can give you a better answer. Either way, it’s a big boom. Wolfram says, it’s about 90 PJ, which is firmly in the nuclear weapons territory.

    • MojoMcJojo@lemmy.world
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      1 day ago

      A lot Please, please, please, someone check my googled physics and AI math:

      E = mc² = 1 kg × (3×10⁸ m/s)² = 9×10¹⁶ joules (90,000,000,000,000,000 joules)

      or

      ~21.5 MEGAtons of TNT (by comparison, the Hiroshima bomb was ~15 KILOtons)

      It would have a temperature of ~1.2 × 10²³ K (1,200,000,000,000,000,000,000,000 Kelvin) The sun is a 5,772 Kelvin.

      Like a ‘small’ star, it would radiate energy of about ∼3.6×10³² Watts (3,600,000,000,000,000,000,000,000,000,000,000 W) The sun puts out about 3.8x10²⁶ Watts (380,000,000,000,000,000,000,000,000 W)

      Final burst duration: less than ∼8×10⁻¹⁷ seconds, or slightly faster than it takes for your mom to drop her panties.

      Now for the best part. All of that energy would emanate from a very, and I can’t express this enough, very tiny spot, like a billion times smaller than a proton:

      ~1.5×10⁻²⁷ meters

      A proton is about 10⁻¹⁵

      From seemingly nowhere, instant God-boom. I like to imagine that whatever was next to it would just disappear, and then the shockwave would happen.

      Again, I googled and used AI to run the code for the calculations, so…you know, correct me and downvote.